Optimal. Leaf size=526 \[ -\frac{\tanh ^{-1}\left (\frac{\sqrt{a+c x^2}}{\sqrt{a}}\right )}{a^{3/2} d}-\frac{a \left (a f^2+c \left (e^2-d f\right )\right )+c^2 d e x}{a d \sqrt{a+c x^2} \left ((c d-a f)^2+a c e^2\right )}+\frac{f \left (2 e \left (a f^2+c \left (e^2-2 d f\right )\right )-\left (e-\sqrt{e^2-4 d f}\right ) \left (a f^2+c \left (e^2-d f\right )\right )\right ) \tanh ^{-1}\left (\frac{2 a f-c x \left (e-\sqrt{e^2-4 d f}\right )}{\sqrt{2} \sqrt{a+c x^2} \sqrt{2 a f^2+c \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}\right )}{\sqrt{2} d \sqrt{e^2-4 d f} \left ((c d-a f)^2+a c e^2\right ) \sqrt{2 a f^2+c \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}-\frac{f \left (2 e \left (a f^2+c \left (e^2-2 d f\right )\right )-\left (\sqrt{e^2-4 d f}+e\right ) \left (a f^2+c \left (e^2-d f\right )\right )\right ) \tanh ^{-1}\left (\frac{2 a f-c x \left (\sqrt{e^2-4 d f}+e\right )}{\sqrt{2} \sqrt{a+c x^2} \sqrt{2 a f^2+c \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}\right )}{\sqrt{2} d \sqrt{e^2-4 d f} \left ((c d-a f)^2+a c e^2\right ) \sqrt{2 a f^2+c \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}+\frac{1}{a d \sqrt{a+c x^2}} \]
[Out]
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Rubi [A] time = 4.82784, antiderivative size = 526, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 9, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333 \[ -\frac{\tanh ^{-1}\left (\frac{\sqrt{a+c x^2}}{\sqrt{a}}\right )}{a^{3/2} d}-\frac{a \left (a f^2+c \left (e^2-d f\right )\right )+c^2 d e x}{a d \sqrt{a+c x^2} \left ((c d-a f)^2+a c e^2\right )}+\frac{f \left (2 e \left (a f^2+c \left (e^2-2 d f\right )\right )-\left (e-\sqrt{e^2-4 d f}\right ) \left (a f^2+c \left (e^2-d f\right )\right )\right ) \tanh ^{-1}\left (\frac{2 a f-c x \left (e-\sqrt{e^2-4 d f}\right )}{\sqrt{2} \sqrt{a+c x^2} \sqrt{2 a f^2+c \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}\right )}{\sqrt{2} d \sqrt{e^2-4 d f} \left ((c d-a f)^2+a c e^2\right ) \sqrt{2 a f^2+c \left (-e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}-\frac{f \left (2 e \left (a f^2+c \left (e^2-2 d f\right )\right )-\left (\sqrt{e^2-4 d f}+e\right ) \left (a f^2+c \left (e^2-d f\right )\right )\right ) \tanh ^{-1}\left (\frac{2 a f-c x \left (\sqrt{e^2-4 d f}+e\right )}{\sqrt{2} \sqrt{a+c x^2} \sqrt{2 a f^2+c \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}\right )}{\sqrt{2} d \sqrt{e^2-4 d f} \left ((c d-a f)^2+a c e^2\right ) \sqrt{2 a f^2+c \left (e \sqrt{e^2-4 d f}-2 d f+e^2\right )}}+\frac{1}{a d \sqrt{a+c x^2}} \]
Antiderivative was successfully verified.
[In] Int[1/(x*(a + c*x^2)^(3/2)*(d + e*x + f*x^2)),x]
[Out]
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Rubi in Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(1/x/(c*x**2+a)**(3/2)/(f*x**2+e*x+d),x)
[Out]
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Mathematica [A] time = 2.17868, size = 889, normalized size = 1.69 \[ \frac{c (c (d-e x)-a f)}{a \left (c^2 d^2+a^2 f^2+a c \left (e^2-2 d f\right )\right ) \sqrt{c x^2+a}}+\frac{\log (x)}{a^{3/2} d}-\frac{f \left (a \left (e+\sqrt{e^2-4 d f}\right ) f^2+c \left (e^3+\sqrt{e^2-4 d f} e^2-3 d f e-d f \sqrt{e^2-4 d f}\right )\right ) \log \left (-e-2 f x+\sqrt{e^2-4 d f}\right )}{\sqrt{2} d \sqrt{e^2-4 d f} \left (c^2 d^2+a^2 f^2+a c \left (e^2-2 d f\right )\right ) \sqrt{2 a f^2+c \left (e^2-\sqrt{e^2-4 d f} e-2 d f\right )}}+\frac{f \left (a \left (e-\sqrt{e^2-4 d f}\right ) f^2+c \left (e^3-\sqrt{e^2-4 d f} e^2-3 d f e+d f \sqrt{e^2-4 d f}\right )\right ) \log \left (e+2 f x+\sqrt{e^2-4 d f}\right )}{\sqrt{2} d \sqrt{e^2-4 d f} \left (c^2 d^2+a^2 f^2+a c \left (e^2-2 d f\right )\right ) \sqrt{2 a f^2+c \left (e^2+\sqrt{e^2-4 d f} e-2 d f\right )}}-\frac{\log \left (a+\sqrt{c x^2+a} \sqrt{a}\right )}{a^{3/2} d}+\frac{f \left (a \left (e+\sqrt{e^2-4 d f}\right ) f^2+c \left (e^3+\sqrt{e^2-4 d f} e^2-3 d f e-d f \sqrt{e^2-4 d f}\right )\right ) \log \left (2 a f+c \left (\sqrt{e^2-4 d f}-e\right ) x+\sqrt{2 c e^2-2 c \sqrt{e^2-4 d f} e+4 a f^2-4 c d f} \sqrt{c x^2+a}\right )}{\sqrt{2} d \sqrt{e^2-4 d f} \left (c^2 d^2+a^2 f^2+a c \left (e^2-2 d f\right )\right ) \sqrt{2 a f^2+c \left (e^2-\sqrt{e^2-4 d f} e-2 d f\right )}}+\frac{f \left (a \left (\sqrt{e^2-4 d f}-e\right ) f^2+c \left (-e^3+\sqrt{e^2-4 d f} e^2+3 d f e-d f \sqrt{e^2-4 d f}\right )\right ) \log \left (-2 a f+c e x+c \sqrt{e^2-4 d f} x-\sqrt{4 a f^2+2 c \left (e^2+\sqrt{e^2-4 d f} e-2 d f\right )} \sqrt{c x^2+a}\right )}{\sqrt{2} d \sqrt{e^2-4 d f} \left (c^2 d^2+a^2 f^2+a c \left (e^2-2 d f\right )\right ) \sqrt{2 a f^2+c \left (e^2+\sqrt{e^2-4 d f} e-2 d f\right )}} \]
Antiderivative was successfully verified.
[In] Integrate[1/(x*(a + c*x^2)^(3/2)*(d + e*x + f*x^2)),x]
[Out]
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Maple [B] time = 0.023, size = 1945, normalized size = 3.7 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(1/x/(c*x^2+a)^(3/2)/(f*x^2+e*x+d),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{{\left (c x^{2} + a\right )}^{\frac{3}{2}}{\left (f x^{2} + e x + d\right )} x}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((c*x^2 + a)^(3/2)*(f*x^2 + e*x + d)*x),x, algorithm="maxima")
[Out]
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((c*x^2 + a)^(3/2)*(f*x^2 + e*x + d)*x),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{x \left (a + c x^{2}\right )^{\frac{3}{2}} \left (d + e x + f x^{2}\right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/x/(c*x**2+a)**(3/2)/(f*x**2+e*x+d),x)
[Out]
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GIAC/XCAS [F(-2)] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: TypeError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((c*x^2 + a)^(3/2)*(f*x^2 + e*x + d)*x),x, algorithm="giac")
[Out]